What is the power consumed by a 500 OHM resistor with a voltage of 1,732 volts?

Prepare for the CWEA Mechanical Technologist Grade 1 Exam. Use flashcards and multiple choice questions, complete with hints and explanations, to gear up for your certification!

To find the power consumed by a resistor, you can use the formula derived from Ohm's Law and the power equations, specifically:

[ P = \frac{V^2}{R} ]

where ( P ) is the power in watts, ( V ) is the voltage in volts, and ( R ) is the resistance in ohms.

In this case, the voltage ( V ) is 1,732 volts and the resistance ( R ) is 500 ohms. Plugging these values into the formula:

[ P = \frac{(1,732)^2}{500} ]

Calculating ( (1,732)^2 ) gives 2,999,584. Now, divide this value by 500:

[ P = \frac{2,999,584}{500} = 5,999.168 ]

Rounding this result gives approximately 5,999.65 watts.

Thus, the power consumed by the 500 ohm resistor at 1,732 volts is correctly calculated as 5,999.65 watts. This method effectively demonstrates the relationship between voltage, resistance, and power, reinforcing the concept of how they interrelate according to Oh

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